X^2-40x+156=0

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Solution for X^2-40x+156=0 equation:



X^2-40X+156=0
a = 1; b = -40; c = +156;
Δ = b2-4ac
Δ = -402-4·1·156
Δ = 976
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:
$\sqrt{\Delta}=\sqrt{976}=\sqrt{16*61}=\sqrt{16}*\sqrt{61}=4\sqrt{61}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-40)-4\sqrt{61}}{2*1}=\frac{40-4\sqrt{61}}{2} $
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-40)+4\sqrt{61}}{2*1}=\frac{40+4\sqrt{61}}{2} $

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